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[bugfix] fixes https://github.com/nim-lang/Nim/issues/11430

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[bugfix] fixes https://github.com/nim-lang/Nim/issues/11430
This commit is contained in:
Andreas Rumpf
2019-06-15 11:29:10 +02:00
committed by GitHub
parent 68cce40510 6dc6487311
commit eadea343ef
3 changed files with 61 additions and 27 deletions
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60
lib/pure/strutils.nim
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@@ -1850,9 +1850,11 @@ proc find*(s: string, sub: char, start: Natural = 0, last = 0): int {.noSideEffe
## If `last` is unspecified, it defaults to `s.high` (the last element).
##
## Searching is case-sensitive. If `sub` is not in `s`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].rfind` for a ``start``-origin index.
##
## See also:
## * `rfind proc<#rfind,string,char,int>`_
## * `rfind proc<#rfind,string,char,int,int>`_
## * `replace proc<#replace,string,char,char>`_
let last = if last==0: s.high else: last
when nimvm:
@@ -1876,9 +1878,11 @@ proc find*(s: string, chars: set[char], start: Natural = 0, last = 0): int {.noS
## If `last` is unspecified, it defaults to `s.high` (the last element).
##
## If `s` contains none of the characters in `chars`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].find` for a ``start``-origin index.
##
## See also:
## * `rfind proc<#rfind,string,set[char],int>`_
## * `rfind proc<#rfind,string,set[char],int,int>`_
## * `multiReplace proc<#multiReplace,string,varargs[]>`_
let last = if last==0: s.high else: last
for i in int(start)..last:
@@ -1891,9 +1895,11 @@ proc find*(s, sub: string, start: Natural = 0, last = 0): int {.noSideEffect,
## If `last` is unspecified, it defaults to `s.high` (the last element).
##
## Searching is case-sensitive. If `sub` is not in `s`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].find` for a ``start``-origin index.
##
## See also:
## * `rfind proc<#rfind,string,string,int>`_
## * `rfind proc<#rfind,string,string,int,int>`_
## * `replace proc<#replace,string,string,string>`_
if sub.len > s.len: return -1
if sub.len == 1: return find(s, sub[0], start, last)
@@ -1901,45 +1907,59 @@ proc find*(s, sub: string, start: Natural = 0, last = 0): int {.noSideEffect,
initSkipTable(a, sub)
result = find(a, s, sub, start, last)
proc rfind*(s: string, sub: char, start: int = -1): int {.noSideEffect,
rtl.} =
## Searches for characer `sub` in `s` in reverse, starting at position `start`
## (default: the last character) and going backwards to the first character.
proc rfind*(s: string, sub: char, start: Natural = 0, last = -1): int {.noSideEffect,
rtl, extern: "nsuRFindChar".} =
## Searches for `sub` in `s` inside range ``start..last`` (both ends included)
## in reverse -- starting at high indexes and moving lower to the first
## character or ``start``. If `last` is unspecified, it defaults to `s.high`
## (the last element).
##
## Searching is case-sensitive. If `sub` is not in `s`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].find` for a ``start``-origin index.
##
## See also:
## * `find proc<#find,string,char,int,int>`_
let realStart = if start == -1: s.len-1 else: start
for i in countdown(realStart, 0):
let last = if last == -1: s.high else: last
for i in countdown(last, start):
if sub == s[i]: return i
return -1
proc rfind*(s: string, chars: set[char], start: int = -1): int {.noSideEffect.} =
## Searches for `chars` in `s` in reverse, starting at position `start`
## (default: the last character) and going backwards to the first character.
proc rfind*(s: string, chars: set[char], start: Natural = 0, last = -1): int {.noSideEffect,
rtl, extern: "nsuRFindCharSet".} =
## Searches for `chars` in `s` inside range ``start..last`` (both ends
## included) in reverse -- starting at high indexes and moving lower to the
## first character or ``start``. If `last` is unspecified, it defaults to
## `s.high` (the last element).
##
## Searching is case-sensitive. If `sub` is not in `s`, -1 is returned.
## If `s` contains none of the characters in `chars`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].rfind` for a ``start``-origin index.
##
## See also:
## * `find proc<#find,string,set[char],Natural,int>`_
let realStart = if start == -1: s.len-1 else: start
for i in countdown(realStart, 0):
let last = if last == -1: s.high else: last
for i in countdown(last, start):
if s[i] in chars: return i
return -1
proc rfind*(s, sub: string, start: int = -1): int {.noSideEffect.} =
## Searches for string `sub` in `s` in reverse, starting at position `start`
## (default: the last character) and going backwards to the first character.
proc rfind*(s, sub: string, start: Natural = 0, last = -1): int {.noSideEffect,
rtl, extern: "nsuRFindStr".} =
## Searches for `sub` in `s` inside range ``start..last`` (both ends included)
## included) in reverse -- starting at high indexes and moving lower to the
## first character or ``start``. If `last` is unspecified, it defaults to
## `s.high` (the last element).
##
## Searching is case-sensitive. If `sub` is not in `s`, -1 is returned.
## Otherwise the index returned is relative to ``s[0]``, not ``start``.
## Use `s[start..last].rfind` for a ``start``-origin index.
##
## See also:
## * `find proc<#find,string,string,Natural,int>`_
if sub.len == 0:
return -1
let realStart = if start == -1: s.len else: start
for i in countdown(realStart-sub.len, 0):
let last = if last == -1: s.high else: last
for i in countdown(last - sub.len + 1, start):
for j in 0..sub.len-1:
result = i
if sub[j] != s[i+j]: