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82 lines
1.7 KiB
Nim
82 lines
1.7 KiB
Nim
discard """
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output: '''start
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false
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0
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1
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2
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end
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@[2, 4, 6, 8, 10]
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@[4, 8, 12, 16, 20]'''
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"""
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# bug #3837
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proc iter1(): (iterator: int) =
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let coll = [0,1,2]
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result = iterator: int {.closure.} =
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for i in coll:
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yield i
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proc iter2(it: (iterator: int)): (iterator: int) =
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result = iterator: int {.closure.} =
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echo finished(it)
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for i in it():
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yield i
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echo "start"
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let myiter1 = iter1()
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let myiter2 = iter2(myiter1)
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for i in myiter2():
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echo i
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echo "end"
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# start
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# false
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# end
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from sequtils import toSeq
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type Iterable*[T] = (iterator: T) | Slice[T]
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## Everything that can be iterated over, iterators and slices so far.
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proc toIter*[T](s: Slice[T]): iterator: T =
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## Iterate over a slice.
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iterator it: T {.closure.} =
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for x in s.a..s.b:
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yield x
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return it
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proc toIter*[T](i: iterator: T): iterator: T =
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## Nop
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i
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iterator map*[T,S](i: Iterable[T], f: proc(x: T): S): S =
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let i = toIter(i)
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for x in i():
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yield f(x)
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proc filter*[T](i: Iterable[T], f: proc(x: T): bool): iterator: T =
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## Iterates through an iterator and yields every item that fulfills the
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## predicate `f`.
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##
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## .. code-block:: nim
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## for x in filter(1..11, proc(x): bool = x mod 2 == 0):
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## echo x
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let i = toIter(i)
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iterator it: T {.closure.} =
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for x in i():
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if f(x):
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yield x
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result = it
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iterator filter*[T](i: Iterable[T], f: proc(x: T): bool): T =
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let i = toIter(i)
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for x in i():
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if f(x):
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yield x
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var it = toSeq(filter(2..10, proc(x: int): bool = x mod 2 == 0))
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echo it # @[2, 4, 6, 8, 10]
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it = toSeq(map(filter(2..10, proc(x: int): bool = x mod 2 == 0), proc(x: int): int = x * 2))
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echo it # Expected output: @[4, 8, 12, 16, 20], Actual output: @[]
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