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106 lines
2.5 KiB
Odin
106 lines
2.5 KiB
Odin
package slice
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import "base:runtime"
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// An in-place permutation iterator.
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Permutation_Iterator :: struct($T: typeid) {
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index: int,
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slice: []T,
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counters: []int,
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}
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/*
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Make an iterator to permute a slice in-place.
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*Allocates Using Provided Allocator*
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This procedure allocates some state to assist in permutation and does not make
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a copy of the underlying slice. If you want to permute a slice without altering
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the underlying data, use `clone` to create a copy, then permute that instead.
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Inputs:
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- slice: The slice to permute.
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- allocator: (default is context.allocator)
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Returns:
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- iter: The iterator, to be passed to `permute`.
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- error: An `Allocator_Error`, if allocation failed.
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*/
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make_permutation_iterator :: proc(
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slice: []$T,
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allocator := context.allocator,
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) -> (
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iter: Permutation_Iterator(T),
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error: runtime.Allocator_Error,
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) #optional_allocator_error {
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iter.slice = slice
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iter.counters = make([]int, len(iter.slice), allocator) or_return
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return
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}
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/*
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Free the state allocated by `make_permutation_iterator`.
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Inputs:
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- iter: The iterator created by `make_permutation_iterator`.
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- allocator: The allocator used to create the iterator. (default is context.allocator)
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*/
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destroy_permutation_iterator :: proc(
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iter: Permutation_Iterator($T),
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allocator := context.allocator,
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) {
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delete(iter.counters, allocator = allocator)
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}
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/*
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Permute a slice in-place.
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Note that the first iteration will always be the original, unpermuted slice.
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Inputs:
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- iter: The iterator created by `make_permutation_iterator`.
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Returns:
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- ok: True if the permutation succeeded, false if the iteration is complete.
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*/
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permute :: proc(iter: ^Permutation_Iterator($T)) -> (ok: bool) {
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// This is an iterative, resumable implementation of Heap's algorithm.
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//
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// The original algorithm was described by B. R. Heap as "Permutations by
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// interchanges" in The Computer Journal, 1963.
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//
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// This implementation is based on the nonrecursive version described by
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// Robert Sedgewick in "Permutation Generation Methods" which was published
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// in ACM Computing Surveys in 1977.
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i := iter.index
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if i == 0 {
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iter.index = 1
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return true
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}
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n := len(iter.counters)
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#no_bounds_check for i < n {
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if iter.counters[i] < i {
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if i & 1 == 0 {
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iter.slice[0], iter.slice[i] = iter.slice[i], iter.slice[0]
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} else {
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iter.slice[iter.counters[i]], iter.slice[i] = iter.slice[i], iter.slice[iter.counters[i]]
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}
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iter.counters[i] += 1
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i = 1
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break
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} else {
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iter.counters[i] = 0
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i += 1
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}
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}
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if i == n {
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return false
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}
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iter.index = i
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return true
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}
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