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refactor: replace char_u with char

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Work on https://github.com/neovim/neovim/issues/459
This commit is contained in:
Dundar Goc
2022-07-31 16:20:57 +02:00
committed by dundargoc
parent f79773a3b4
commit 094cdf2d69
43 changed files with 499 additions and 537 deletions
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22
src/nvim/regexp.c
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@@ -482,16 +482,14 @@ static char_u *skip_anyof(char *p)
return (char_u *)p;
}
/*
* Skip past regular expression.
* Stop at end of "startp" or where "dirc" is found ('/', '?', etc).
* Take care of characters with a backslash in front of it.
* Skip strings inside [ and ].
* When "newp" is not NULL and "dirc" is '?', make an allocated copy of the
* expression and change "\?" to "?". If "*newp" is not NULL the expression
* is changed in-place.
*/
char_u *skip_regexp(char_u *startp, int dirc, int magic, char_u **newp)
/// Skip past regular expression.
/// Stop at end of "startp" or where "dirc" is found ('/', '?', etc).
/// Take care of characters with a backslash in front of it.
/// Skip strings inside [ and ].
/// When "newp" is not NULL and "dirc" is '?', make an allocated copy of the
/// expression and change "\?" to "?". If "*newp" is not NULL the expression
/// is changed in-place.
char_u *skip_regexp(char_u *startp, int dirc, int magic, char **newp)
{
int mymagic;
char_u *p = startp;
@@ -517,8 +515,8 @@ char_u *skip_regexp(char_u *startp, int dirc, int magic, char_u **newp)
if (dirc == '?' && newp != NULL && p[1] == '?') {
// change "\?" to "?", make a copy first.
if (*newp == NULL) {
*newp = vim_strsave(startp);
p = *newp + (p - startp);
*newp = (char *)vim_strsave(startp);
p = (char_u *)(*newp) + (p - startp);
}
STRMOVE(p, p + 1);
} else {