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vim-patch:9.1.1483: not possible to translation position in buffer (#37099)
Problem: not possible to translation position in buffer
Solution: use _() macro to mark the output as translatable
(Emir SARI)
Row/Column indicator separator is currently not customizable. Some
languages have a space after the comma as the usual practice, plus this
would help translators use a custom separator like colons if necessary.
Additionally, after a save, the line and the byte indicator is also
hardcoded, this enables i18n for that as well.
closes: vim/vim#17608
81f9815831
Co-authored-by: Emir SARI <emir_sari@icloud.com>
This commit is contained in:
@@ -2146,7 +2146,8 @@ void msg_add_lines(int insert_space, linenr_T lnum, off_T nchars)
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size_t len = strlen(IObuff);
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if (shortmess(SHM_LINES)) {
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snprintf(IObuff + len, IOSIZE - len, "%s%" PRId64 "L, %" PRId64 "B",
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snprintf(IObuff + len, IOSIZE - len,
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_("%s%" PRId64 "L, %" PRId64 "B"), // l10n: L as in line, B as in byte
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insert_space ? " " : "", (int64_t)lnum, (int64_t)nchars);
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} else {
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len += (size_t)snprintf(IObuff + len, IOSIZE - len,
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@@ -491,7 +491,10 @@ void redraw_ruler(void)
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#define RULER_BUF_LEN 70
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char buffer[RULER_BUF_LEN];
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int bufferlen = vim_snprintf(buffer, RULER_BUF_LEN, "%" PRId64 ",",
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// row number, column number is appended
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// l10n: leave as-is unless a space after the comma is preferred
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// l10n: do not add any row/column label, due to the limited space
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int bufferlen = vim_snprintf(buffer, RULER_BUF_LEN, _("%" PRId64 ","),
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(wp->w_buffer->b_ml.ml_flags & ML_EMPTY)
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? 0
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: (int64_t)wp->w_cursor.lnum);
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