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clean the docs of sequtils (#16332)
This commit is contained in:
@@ -7,19 +7,19 @@
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# distribution, for details about the copyright.
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#
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## Although this module has ``seq`` in its name, it implements operations
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## Although this module has `seq` in its name, it implements operations
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## not only for `seq`:idx: type, but for three built-in container types under
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## the ``openArray`` umbrella:
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## the `openArray` umbrella:
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## * sequences
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## * strings
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## * array
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##
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## The system module defines several common functions, such as:
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## * ``newSeq[T]`` for creating new sequences of type ``T``
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## * ``@`` for converting arrays and strings to sequences
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## * ``add`` for adding new elements to strings and sequences
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## * ``&`` for string and seq concatenation
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## * ``in`` (alias for ``contains``) and ``notin`` for checking if an item is
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## * `newSeq[T]` for creating new sequences of type `T`
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## * `@` for converting arrays and strings to sequences
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## * `add` for adding new elements to strings and sequences
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## * `&` for string and seq concatenation
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## * `in` (alias for `contains`) and `notin` for checking if an item is
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## in a container
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##
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## This module builds upon that, providing additional functionality in form of
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@@ -37,41 +37,40 @@
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##
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## The chaining of functions is possible thanks to the
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## `method call syntax<manual.html#procedures-method-call-syntax>`_.
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##
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## .. code-block::
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## import sequtils, sugar
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##
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## # Creating a sequence from 1 to 10, multiplying each member by 2,
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## # keeping only the members which are not divisible by 6.
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## let
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## foo = toSeq(1..10).map(x => x*2).filter(x => x mod 6 != 0)
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## bar = toSeq(1..10).mapIt(it*2).filterIt(it mod 6 != 0)
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## baz = collect(newSeq):
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## for i in 1..10:
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## let j = 2*i
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## if j mod 6 != 0:
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## j
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##
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## doAssert foo == bar
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## doAssert foo == baz
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## echo foo # @[2, 4, 8, 10, 14, 16, 20]
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##
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## echo foo.any(x => x > 17) # true
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## echo bar.allIt(it < 20) # false
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## echo foo.foldl(a + b) # 74; sum of all members
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##
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## .. code-block::
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## import sequtils
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## from strutils import join
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##
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## let
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## vowels = @"aeiou" # creates a sequence @['a', 'e', 'i', 'o', 'u']
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## foo = "sequtils is an awesome module"
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##
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## echo foo.filterIt(it notin vowels).join # "sqtls s n wsm mdl"
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##
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## ----
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##
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runnableExamples:
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import sugar
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# Creating a sequence from 1 to 10, multiplying each member by 2,
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# keeping only the members which are not divisible by 6.
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let
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foo = toSeq(1..10).map(x => x*2).filter(x => x mod 6 != 0)
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bar = toSeq(1..10).mapIt(it*2).filterIt(it mod 6 != 0)
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baz = collect:
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for i in 1..10:
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let j = 2*i
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if j mod 6 != 0:
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j
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doAssert foo == bar
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doAssert foo == baz
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doAssert foo == @[2, 4, 8, 10, 14, 16, 20]
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doAssert foo.any(x => x > 17)
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doAssert not bar.allIt(it < 20)
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doAssert foo.foldl(a + b) == 74 # sum of all members
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runnableExamples:
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from strutils import join
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let
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vowels = @"aeiou"
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foo = "sequtils is an awesome module"
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doAssert (vowels is seq[char]) and (vowels == @['a', 'e', 'i', 'o', 'u'])
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doAssert foo.filterIt(it notin vowels).join == "sqtls s n wsm mdl"
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## **See also**:
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## * `strutils module<strutils.html>`_ for common string functions
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## * `sugar module<sugar.html>`_ for syntactic sugar macros
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@@ -90,12 +89,12 @@ when not defined(nimhygiene):
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macro evalOnceAs(expAlias, exp: untyped,
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letAssigneable: static[bool]): untyped =
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## Injects ``expAlias`` in caller scope, to avoid bugs involving multiple
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## Injects `expAlias` in caller scope, to avoid bugs involving multiple
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## substitution in macro arguments such as
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## https://github.com/nim-lang/Nim/issues/7187
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## ``evalOnceAs(myAlias, myExp)`` will behave as ``let myAlias = myExp``
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## except when ``letAssigneable`` is false (e.g. to handle openArray) where
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## it just forwards ``exp`` unchanged
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## `evalOnceAs(myAlias, myExp)` will behave as `let myAlias = myExp`
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## except when `letAssigneable` is false (e.g. to handle openArray) where
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## it just forwards `exp` unchanged
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expectKind(expAlias, nnkIdent)
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var val = exp
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@@ -428,7 +427,10 @@ func apply*[T](s: var openArray[T], op: proc (x: T): T {.closure.})
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func apply*[T](s: openArray[T], op: proc (x: T) {.closure.}) {.inline, since: (1, 3).} =
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## Same as `apply` but for proc that do not return and do not mutate `s` directly.
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runnableExamples: apply([0, 1, 2, 3, 4], proc(item: int) = echo item)
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runnableExamples:
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var message: string
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apply([0, 1, 2, 3, 4], proc(item: int) = message.addInt item)
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assert message == "01234"
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for i in 0 ..< s.len: op(s[i])
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iterator filter*[T](s: openArray[T], pred: proc(x: T): bool {.closure.}): T =
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@@ -576,8 +578,8 @@ template filterIt*(s, pred: untyped): untyped =
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##
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## Unlike the `filter func<#filter,openArray[T],proc(T)>`_ and
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## `filter iterator<#filter.i,openArray[T],proc(T)>`_,
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## the predicate needs to be an expression using the ``it`` variable
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## for testing, like: ``filterIt("abcxyz", it == 'x')``.
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## the predicate needs to be an expression using the `it` variable
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## for testing, like: `filterIt("abcxyz", it == 'x')`.
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##
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## Instead of using `mapIt` and `filterIt`, consider using the `collect` macro
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## from the `sugar` module.
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@@ -601,12 +603,12 @@ template filterIt*(s, pred: untyped): untyped =
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result
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template keepItIf*(varSeq: seq, pred: untyped) =
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## Keeps the items in the passed sequence (must be declared as a ``var``)
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## Keeps the items in the passed sequence (must be declared as a `var`)
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## if they fulfilled the predicate.
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##
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## Unlike the `keepIf func<#keepIf,seq[T],proc(T)>`_,
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## the predicate needs to be an expression using
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## the ``it`` variable for testing, like: ``keepItIf("abcxyz", it == 'x')``.
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## the `it` variable for testing, like: `keepItIf("abcxyz", it == 'x')`.
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##
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## See also:
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## * `keepIf func<#keepIf,seq[T],proc(T)>`_
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@@ -634,7 +636,7 @@ since (1, 1):
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## Returns a count of all the items that fulfilled the predicate.
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##
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## The predicate needs to be an expression using
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## the ``it`` variable for testing, like: ``countIt(@[1, 2, 3], it > 2)``.
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## the `it` variable for testing, like: `countIt(@[1, 2, 3], it > 2)`.
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##
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runnableExamples:
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let numbers = @[-3, -2, -1, 0, 1, 2, 3, 4, 5, 6]
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@@ -672,7 +674,7 @@ template allIt*(s, pred: untyped): bool =
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##
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## Unlike the `all func<#all,openArray[T],proc(T)>`_,
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## the predicate needs to be an expression using
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## the ``it`` variable for testing, like: ``allIt("abba", it == 'a')``.
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## the `it` variable for testing, like: `allIt("abba", it == 'a')`.
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##
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## See also:
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## * `all func<#all,openArray[T],proc(T)>`_
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@@ -714,7 +716,7 @@ template anyIt*(s, pred: untyped): bool =
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##
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## Unlike the `any func<#any,openArray[T],proc(T)>`_,
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## the predicate needs to be an expression using
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## the ``it`` variable for testing, like: ``anyIt("abba", it == 'a')``.
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## the `it` variable for testing, like: `anyIt("abba", it == 'a')`.
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##
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## See also:
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## * `any func<#any,openArray[T],proc(T)>`_
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@@ -817,10 +819,10 @@ template foldl*(sequence, operation: untyped): untyped =
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## The sequence is required to have at least a single element. Debug versions
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## of your program will assert in this situation but release versions will
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## happily go ahead. If the sequence has a single element it will be returned
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## without applying ``operation``.
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## without applying `operation`.
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##
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## The ``operation`` parameter should be an expression which uses the
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## variables ``a`` and ``b`` for each step of the fold. Since this is a left
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## The `operation` parameter should be an expression which uses the
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## variables `a` and `b` for each step of the fold. Since this is a left
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## fold, for non associative binary operations like subtraction think that
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## the sequence of numbers 1, 2 and 3 will be parenthesized as (((1) - 2) -
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## 3).
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@@ -863,12 +865,12 @@ template foldl*(sequence, operation: untyped): untyped =
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template foldl*(sequence, operation, first): untyped =
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## Template to fold a sequence from left to right, returning the accumulation.
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##
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## This version of ``foldl`` gets a **starting parameter**. This makes it possible
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## This version of `foldl` gets a **starting parameter**. This makes it possible
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## to accumulate the sequence into a different type than the sequence elements.
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##
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## The ``operation`` parameter should be an expression which uses the variables
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## ``a`` and ``b`` for each step of the fold. The ``first`` parameter is the
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## start value (the first ``a``) and therefor defines the type of the result.
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## The `operation` parameter should be an expression which uses the variables
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## `a` and `b` for each step of the fold. The `first` parameter is the
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## start value (the first `a`) and therefor defines the type of the result.
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##
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## See also:
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## * `foldr template<#foldr.t,untyped,untyped>`_
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@@ -893,10 +895,10 @@ template foldr*(sequence, operation: untyped): untyped =
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## The sequence is required to have at least a single element. Debug versions
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## of your program will assert in this situation but release versions will
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## happily go ahead. If the sequence has a single element it will be returned
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## without applying ``operation``.
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## without applying `operation`.
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##
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## The ``operation`` parameter should be an expression which uses the
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## variables ``a`` and ``b`` for each step of the fold. Since this is a right
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## The `operation` parameter should be an expression which uses the
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## variables `a` and `b` for each step of the fold. Since this is a right
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## fold, for non associative binary operations like subtraction think that
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## the sequence of numbers 1, 2 and 3 will be parenthesized as (1 - (2 -
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## (3))).
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@@ -936,7 +938,7 @@ template mapIt*(s: typed, op: untyped): untyped =
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## Since the input is not modified you can use it to
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## transform the type of the elements in the input container.
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##
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## The template injects the ``it`` variable which you can use directly in an
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## The template injects the `it` variable which you can use directly in an
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## expression.
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##
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## Instead of using `mapIt` and `filterIt`, consider using the `collect` macro
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@@ -1005,9 +1007,9 @@ template mapIt*(s: typed, op: untyped): untyped =
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map(s, f)
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template applyIt*(varSeq, op: untyped) =
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## Convenience template around the mutable ``apply`` func to reduce typing.
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## Convenience template around the mutable `apply` func to reduce typing.
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##
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## The template injects the ``it`` variable which you can use directly in an
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## The template injects the `it` variable which you can use directly in an
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## expression. The expression has to return the same type as the sequence you
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## are mutating.
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##
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@@ -1064,42 +1066,32 @@ func mapLitsImpl(constructor: NimNode; op: NimNode; nested: bool;
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macro mapLiterals*(constructor, op: untyped;
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nested = true): untyped =
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## Applies ``op`` to each of the **atomic** literals like ``3``
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## or ``"abc"`` in the specified ``constructor`` AST. This can
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## Applies `op` to each of the **atomic** literals like `3`
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## or `"abc"` in the specified `constructor` AST. This can
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## be used to map every array element to some target type:
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##
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## Example:
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##
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## .. code-block::
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## let x = mapLiterals([0.1, 1.2, 2.3, 3.4], int)
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## doAssert x is array[4, int]
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##
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## Short notation for:
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##
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## .. code-block::
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## let x = [int(0.1), int(1.2), int(2.3), int(3.4)]
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##
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## If ``nested`` is true (which is the default), the literals are replaced
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## everywhere in the ``constructor`` AST, otherwise only the first level
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runnableExamples:
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let x = mapLiterals([0.1, 1.2, 2.3, 3.4], int)
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doAssert x is array[4, int]
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doAssert x == [int(0.1), int(1.2), int(2.3), int(3.4)]
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## If `nested` is true (which is the default), the literals are replaced
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## everywhere in the `constructor` AST, otherwise only the first level
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## is considered:
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##
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## .. code-block::
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## let a = mapLiterals((1.2, (2.3, 3.4), 4.8), int)
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## let b = mapLiterals((1.2, (2.3, 3.4), 4.8), int, nested=false)
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## assert a == (1, (2, 3), 4)
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## assert b == (1, (2.3, 3.4), 4)
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##
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## let c = mapLiterals((1, (2, 3), 4, (5, 6)), `$`)
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## let d = mapLiterals((1, (2, 3), 4, (5, 6)), `$`, nested=false)
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## assert c == ("1", ("2", "3"), "4", ("5", "6"))
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## assert d == ("1", (2, 3), "4", (5, 6))
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##
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## There are no constraints for the ``constructor`` AST, it
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runnableExamples:
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let a = mapLiterals((1.2, (2.3, 3.4), 4.8), int)
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let b = mapLiterals((1.2, (2.3, 3.4), 4.8), int, nested=false)
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assert a == (1, (2, 3), 4)
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assert b == (1, (2.3, 3.4), 4)
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let c = mapLiterals((1, (2, 3), 4, (5, 6)), `$`)
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let d = mapLiterals((1, (2, 3), 4, (5, 6)), `$`, nested=false)
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assert c == ("1", ("2", "3"), "4", ("5", "6"))
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assert d == ("1", (2, 3), "4", (5, 6))
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## There are no constraints for the `constructor` AST, it
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## works for nested tuples of arrays of sets etc.
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result = mapLitsImpl(constructor, op, nested.boolVal)
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iterator items*[T](xs: iterator: T): T =
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## iterates over each element yielded by a closure iterator. This may
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## Iterates over each element yielded by a closure iterator. This may
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## not seem particularly useful on its own, but this allows closure
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## iterators to be used by the mapIt, filterIt, allIt, anyIt, etc.
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## templates.
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